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Question 524377: stacey spent $117 on 8 rose bushes and 7 pots of ivy. phil spent $45 on 2 rose bushes and 7 pots of ivy. what is the cost of one rose bush and the cost of one pot of ivy
Answer by lagbens(14)   (Show Source):
You can put this solution on YOUR website! okay, from the given info we easily build a system of equation of 2 variables .
we'll call a variable "R" rep. the rose bushes
and the other one "P" rep. the pots of ivy.
we can write: 8R+7P=117 (eq. 1)
2R+7P=45 (eq. 2)
let's solve this one by the addition method.
to do so we have to eliminate a variable, we're gonna multiply the whole 2nd eq. by -1 in order to eliminate "P"
8R+7P=117
-2R-7P=-45 (add common terms up)
6R=72(divide both side by 6)
R=12.
now all we gotta do is replacing R's value in one of the original equations to find P.
in (eq. 2) it would be: 2(12)+7P=45
24+7p=45(subtract 24 from both side)
7P=21(divide both side by 7)
P=3. final answer [one rose bush costs $12, and one pot ivy costs $3]
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