SOLUTION: A train leaves the station at 6:00pm traveling west at 80mph. On a parallel track,a second train leaves the station 3 hours later traveling west at 100mph, At what time will second
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Question 524332: A train leaves the station at 6:00pm traveling west at 80mph. On a parallel track,a second train leaves the station 3 hours later traveling west at 100mph, At what time will second trdain catch up with the first? Found 2 solutions by Alan3354, josmiceli:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A train leaves the station at 6:00pm traveling west at 80mph. On a parallel track,a second train leaves the station 3 hours later traveling west at 100mph, At what time will second trdain catch up with the first?
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In 3 hours, the 1st train is 240 miles away (80*3)
The 2nd train gains on it at 20 mi/hr (100 - 80)
240/20 = 12 hours from 9 PM to catch up
You can put this solution on YOUR website! The 1st train to leave has a head start of mi
Start a stopwatch when the 2nd train leaves
the station. Both trains will now travel for
the same amount of time.
Let = the time on stopwatch for both trains
Let = the distance the 2nd train travels
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For 2nd train:
(1)
For 1st train:
(2)
Substitute (1) into (2)
(2)
(2)
(2)
The 2nd train will catch up to the 1st 12 hours after
the 2nd train leaves station at 6:00 + 3 hrs = 9:00 PM
That would be 9:00 AM the next morning.
check answer:
(1)
(1)
(1) ( distance from station to where they meet )
and
(2)
(2)
(2)
(2)
OK
