SOLUTION: One leg of a right triangle is one in. more than twice the other leg. the hypotenuse is square root 29 in long. Find the lengths of the legs

Algebra ->  Square-cubic-other-roots -> SOLUTION: One leg of a right triangle is one in. more than twice the other leg. the hypotenuse is square root 29 in long. Find the lengths of the legs      Log On


   

Question 524147: One leg of a right triangle is one in. more than twice the other leg. the hypotenuse is square root 29 in long. Find the lengths of the legs
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
one leg = x
other leg = 2x+1
hypotenuse = sqrt(29)
Using Pythagoras theorem
leg1^2+leg^2=hyp^2
x^2+(2x+1)^2=(sqrt(29))^2
x^2+4x^2+4x+1=29
5x^2+4x-28=0
Find the roots of the equation by quadratic formula

a= 5 ,b= 4 ,c= -28
b^2-4ac=
b^2-4ac= 16 - 560
b^2-4ac= 576 sqrt%28%09576%09%29= 24
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( -4 + 24 )/ 10
x1= 2
x2=( -4 -24 ) / 10
x2= -2.8
Ignore negative value
one leg = 2
other leg =>2x+1=>5
m.ananth@hotmail.com