Question 524141: The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a women weighs 119 pounds when she is at sea level, 3960 miles from the center of Earth, how much will she weigh when she is at the top of a mountain, 1.8 miles above sea level?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The weight of a body above sea level varies inversely with the square of the distance from the center of Earth.
w = k/d^2
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Solve for "k" using "a women weighs 119 pounds when she is at sea level, 3960 miles from the center of Earth"
119 = k/(3960)^2
k = [119*3960^2]
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Equation:
w = [119*3960^2]/d^2
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How much will she weigh when she is at the top of a mountain, 1.8 miles above sea level?
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Ans: w = [119*3960^2]/(3960+1.8)^2
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weight = 118.89 lbs
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Cheers,
Stan H.
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