SOLUTION: I had to find the second derivative of 3-4/x-2/x^2, in which I came up with -8/x^3-12/x^4. I need help factoring that equation???
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: I had to find the second derivative of 3-4/x-2/x^2, in which I came up with -8/x^3-12/x^4. I need help factoring that equation???
Log On
Question 524096: I had to find the second derivative of 3-4/x-2/x^2, in which I came up with -8/x^3-12/x^4. I need help factoring that equation??? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! I had to find the second derivative of 3-4/x-2/x^2, in which I came up with -8/x^3-12/x^4. I need help factoring that equation???
-----------
What equation? I don't see an equal sign.
--------
Do you want to factor 8/x^3-12/x^4 ? why?
You can rewrite it as (8x-12)/x^4 or 4(x-3)/x^4
