SOLUTION: Joan has $4.50 in nickels, dimes, and quarters. There are twice as many dimes as nickels, and two more quarters than nickels. How many of each type of coin does she have?

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Question 524072: Joan has $4.50 in nickels, dimes, and quarters. There are twice as many dimes as nickels, and two more quarters than nickels. How many of each type of coin does she have?
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents
q = number of quarters
25q = value of quarters in cents
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5n + 10d + 25q = 450 cents
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d = 2n
q = n+2
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5n + 10(2n) + 25(n+2) = 450
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5n + 20n +25n +50 = 450
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50n = 400
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n = 8
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d = 2(8) = 16
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q = n+2 = 10
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Check the values
.
5*8 = 40 cents
10*16 = 160 cents
25*10 = 250 cents
40 + 160 + 250 = 450 cents
Correct.
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Answer: 8 nickels, 16 dimes, and 10 quarters.
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Done.