SOLUTION: An object is projected vertically upward from the top of a building with an initial velocity of 128 ft/sec. Its distance s(t) in feet above the ground after t seconds is given by t
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Question 523986: An object is projected vertically upward from the top of a building with an initial velocity of 128 ft/sec. Its distance s(t) in feet above the ground after t seconds is given by the equation s(t) = −16t2 + 128t + 120.
A.)Find maximum distance above the ground.
B.)Find the height of the building. Answer by solver91311(24713) (Show Source):
Do you want the Algebra solution or the Calculus solution for part a? Either way, the height of the building is the height of the projectile at time zero. Substitute 0 for and do the arithmetic.
John
My calculator said it, I believe it, that settles it
