SOLUTION: How do I find the height of a triangle if I am only given the length of 2 sides?
Problem:
In ΔABC, AB = 24 cm and BC = 15 cm.
CD bisects AB.
ΔCDB is a right triangl
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-> SOLUTION: How do I find the height of a triangle if I am only given the length of 2 sides?
Problem:
In ΔABC, AB = 24 cm and BC = 15 cm.
CD bisects AB.
ΔCDB is a right triangl
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Question 523965: How do I find the height of a triangle if I am only given the length of 2 sides?
Problem:
In ΔABC, AB = 24 cm and BC = 15 cm.
CD bisects AB.
ΔCDB is a right triangle.
You are given a lot more than just the measure of two sides, though I have to simply assume that point D is on the segment (you didn't specifically say so and you didn't provide a diagram). With that presumption, knowing that bisects and that is right, then CD is a perpendicular bisector of AB. That means that is congruent to (by SAS) and ABC is an isosceles triangle with C as the apex and AB as the base. Further, you know that . From that you can see that is a right triangle with a leg that measures 12 and a hypotenuse that measures 15. You can either use Pythagoras or recognize a 3-4-5 proportion right triangle to determine that the short leg, specifically , measures 9. From that you calculate the area by base times height divided by 2.
John
My calculator said it, I believe it, that settles it
