SOLUTION: How do you graph the equation (x+1/2)^2+ (y-1/3)^2=1

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Question 52381: How do you graph the equation (x+1/2)^2+ (y-1/3)^2=1
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
This is the equation of a circle.
+%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 is the equation of a circle with center at (h,k) and of radius 1.

In this case +%28x%2B1%2F2%29%5E2%2B+%28y-1%2F3%29%5E2=1+ is a circle with center at (-1%2F2, 1%2F3) and radius 1.

R^2 at SCC