SOLUTION: You are a researcher who administered a self-esteem measure to 100 participants. The mean self-esteem score for your sample is 52.45 and the standard deviation of the population i
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Question 523806: You are a researcher who administered a self-esteem measure to 100 participants. The mean self-esteem score for your sample is 52.45 and the standard deviation of the population is 6.28. What is the 90 % confidence interval?
You can put this solution on YOUR website! (a,b)=m+-z[a/2]* s/sqrt(n)
=52.45+-1.645 * 6.28/10
=52.45 +- 1.033
=(53.48, 51.42) the 90 % confidence interval.
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Ed