SOLUTION: 16x-12y=44 and 1/(14x-8) - 1/(6y-14)=1/4 .Calculate x and y for the above equations?

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Question 523756: 16x-12y=44 and 1/(14x-8) - 1/(6y-14)=1/4 .Calculate x and y for the above equations?
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
16x-12y=44
/4
4x-3y=11
3y=4x-11
multiply by 2
6y=8x-22
substitute 6y in equation
1%2F%2814x-8%29+-+1%2F%286y-14%29=1%2F4+
1%2F%2814x-8%29+-1%2F%288x-22-14%29=1%2F4
LCD = 4(14x-8)(8x-36)
4%288x-36%29-4%2814x-8%29=%2814x-8%29%288x-36%29
32x-144-56x%2B32=112x%5E2--504-64x%2B288
Add like terms
112x^2-528x+400=0
/16
7x^2-34x+25=0
Find the roots of the equation by quadratic formula

a= 7 ,b= -34 ,c= 25

b^2-4ac= 1156 + -700
b^2-4ac= 456
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-12%2B21%29%2F%2814%29
x1=( 34 + 21.35 )/ 14
x1= 3.95
x2=( 34 -21.35 ) / 14
x2= 0.9
3y=4x-11
plug x=3.95
3y=4*3.95-11
y=(4*3.95-11)/3
y=1.6
(3.95,1.6)
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3y=4x-11
plug x=0.9
3y=4*0.9-11
y=(4*0.9-11)/3
y=-2.46
(0.9,-2.46)
m.ananth@hotmail.ca