SOLUTION: A model iin new orleans charges $90.00 dollars a day for a double occupacy, and they charge $80.00 for a single occupacy. If 80 rooms are occupied for a total of 6930, how many roo

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A model iin new orleans charges $90.00 dollars a day for a double occupacy, and they charge $80.00 for a single occupacy. If 80 rooms are occupied for a total of 6930, how many roo      Log On


   

Question 523692: A model iin new orleans charges $90.00 dollars a day for a double occupacy, and they charge $80.00 for a single occupacy. If 80 rooms are occupied for a total of 6930, how many rooms of eachkind are occupied?
Answer by Maths68(1474) About Me  (Show Source):
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Let
Number of Double Occupancy rooms = x
Number of Single Occupancy rooms = 80-x
Given
Charges for Double Occupancy room = $90
Charges for Single Occupancy room = $80
Total Charges = $6930
Charges of Double Occupancy rooms * Number of Rooms + Charges for Single Occupancy * Number of Rooms = Total Charges
90*x + 80*(80-x)=6930
90x+6400-80x=6930
-10x=6930-6400
-10x=530
-10x/-10=530/-10
x=53


Number of Double Occupancy rooms = x = 53
Number of Single Occupancy rooms = 80-x = 80-53 = 27

Check
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90*53+27*80=6930
4770+2160=6930
6930=6930