SOLUTION: . . Then for x between -1 and 1, y would be negative? But I am unsure about when {{{x<-1}}} because wouldn't the values for y need to be positive even integers for (-x)^y to be pos

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: . . Then for x between -1 and 1, y would be negative? But I am unsure about when {{{x<-1}}} because wouldn't the values for y need to be positive even integers for (-x)^y to be pos      Log On


   



Question 523270: . . Then for x between -1 and 1, y would be negative? But I am unsure about when x%3C-1 because wouldn't the values for y need to be positive even integers for (-x)^y to be positive? I think I might be getting myself a little confused, I would appreciate any help or advice. Thank you.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Is that the same question? About x^y = 10 ?