SOLUTION: Let be a standard normal random variable. Use the calculator provided to determine the value of such that
P(0.64 less then or equal to Z less then or equal to C)= .2389
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-> SOLUTION: Let be a standard normal random variable. Use the calculator provided to determine the value of such that
P(0.64 less then or equal to Z less then or equal to C)= .2389
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Question 523260: Let be a standard normal random variable. Use the calculator provided to determine the value of such that
P(0.64 less then or equal to Z less then or equal to C)= .2389 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use the calculator provided to determine the value of such that
P(0.64 less then or equal to Z less then or equal to C)= .2389
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Draw a standard normal curve.
Mark 0.64 to the right of zero
Find a z-value to the right of 0.64 with 0.2389 population between them.
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Procedure:
Find area to the left of 0.64: normalcdf(-100,0.64) = 0.7389
Add 0.7389+0.2389 = 0.9778
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Find the z-value with a left-tail of 0.9778: invNorm(0.9778) = 2.0106
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Cheers,
Stan H.
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