SOLUTION: Solve the equation on the interval 0< theta < 2pi sec^2theta+tan theta=0

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Question 523103: Solve the equation on the interval 0< theta < 2pi
sec^2theta+tan theta=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation on the interval 0< theta < 2pi
sec^2theta+tan theta=0
**
using x in place of theta
sec^x+tanx=0
tan^2x+1+tanx=0
tan^2x+tanx+1=0
solve for tanx by quadratic formula:
..
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
..
a=1, b=1, c=1
√(b^2-4ac)=√(1-4)=√(-3)
Therefore, no real solution