Question 523017:  Please help me, I need to get through this test to finish school. 
 
1. Multiply and Simplify
 
4y^2/5y^2-40y+80 * 5y-20/2y =  
 
(Type and Exponential notation with positive exponents)
 
2. Multiply
 
(8x+6)(5x^2+5x+8)
 
3. Evaluate the Polynomial for x=6
 
2x^2-5x+7=
 
4. Solve. 
 
(x+19)(x-2)(x+10)>0
 
Select the correct choice below and if necessary, fill in the answer box to complete your choice.
 
A. The solution set is {|x| } 
B. The solution is all real numbers  
C. There is no solution. 
  
 
 Answer by stanbon(75887)      (Show Source): 
You can  put this solution on YOUR website! 1. Multiply and Simplify  
4y^2/(5y^2-40y+80) * (5y-20)/2y  
------------- 
= (4y^2)/[5(y-4)^2] * (5(y-4))/(2y) 
---- 
Cancel where you can to get: 
= (2y)/(y-4) 
======================================
 
2. Multiply  
(8x+6)(5x^2+5x+8) 
---- 
= (8x)(5x^2+5x+8) + 6(5x^2+5x+8) 
---- 
= 40x^3+40x^2+64x + 30x^2+30x+48 
---- 
= 40x^3+70x^2+94x+48 
====================================== 
  
3. Evaluate the Polynomial for x=6  
2x^2-5x+7= 2(36)-5(6)+7 = 72-30+7 = 49 
===========================================  
4. Solve.  
(x+19)(x-2)(x+10)>0 
Draw a number line. 
Plot x = -19 ; x = -10 ; x = 2 
Test a value in each of the 4 intervals to see where the solutions are. 
(x+19)(x-2)(x+10)>0 
-- 
Test x = -25 to get: -*-*- > 0; false 
Test x = -15 to get: +*-*- > 0; true so solutions in(-19,-10) 
Test x = 0 to get:: +*-*+ > 0; false 
Test x = 5 to get:: +*+*+ > 0; true so solutions in (2,+oo) 
--- 
Solution: {x | -19< x < -10 or 2< x <+oo} 
============================================== 
Cheers, 
Stan H. 
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Select the correct choice below and if necessary, fill in the answer box to complete your choice.  
A. The solution set is {|x| } 
B. The solution is all real numbers  
C. There is no solution.
 
 
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