SOLUTION: if x^2 + y^2 = 10 and (x - y)^2 = 2 find the numerical value of xy.
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Question 522992
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if x^2 + y^2 = 10 and (x - y)^2 = 2 find the numerical value of xy.
Answer by
mananth(16946)
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x^2 + y^2 = 10 -------------(1)
(x - y)^2 = 2
x^2+y^2-2xy =2---------------(2)
(1)-(2)
2xy=10-2
2xy=8
xy=4
xy.