SOLUTION: What are the solutions to the equation: y = x^3 + 3x^2-4x-12
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Question 522928
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What are the solutions to the equation: y = x^3 + 3x^2-4x-12
Answer by
oberobic(2304)
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y = x^3 + 3x^2-4x-12
.
.
zeroes are x = -3, -2, and 2
.
(x+3)(x+2)(x-2)