You can put this solution on YOUR website! What is the area of an isosceles triangle with the base angles of 57degrees and a base of 15
----
Sketch the triangle with base 15 and base angles 57 degrees.
---
Draw a perpendicular bisector of the base.
That bisector is the altitute of the triangle.
----
You have a right triangle on the right side
with base = 15/2 = 7.5
----
Solve tan(57) = alt/7.5
altitude = 7.5*tan(57) = 11.55
----
Area = (1/2)base*altitude
A = (1/2)*7.5*11.55 = 43.31 sq units
===========
Cheers,
Stan H.
(