SOLUTION: Find all solutions of the equation in the interval [0, 2pi). sin(2x)=((-sqrt(3))/2)

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Question 522763: Find all solutions of the equation in the interval [0, 2pi).
sin(2x)=((-sqrt(3))/2)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
sin(2x)=((-sqrt(3))/2)
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2x = 240, 300, 600, 660 degs
x = 120, 150, 300, 330 degs
or x = 2pi/3, 5pi/6, 5pi/3, 11pi/6 radians