SOLUTION: Please help me solve this :{{{ (-1)/(b^2-4)}}}-{{{(-2)/(b^2-4b-12) }}} Here is what I have I'm not sure if I simiplfied to little or to much my LCD is (b-2)(b+2)(b-6) {{{(-1)(b

Algebra ->  Rational-functions -> SOLUTION: Please help me solve this :{{{ (-1)/(b^2-4)}}}-{{{(-2)/(b^2-4b-12) }}} Here is what I have I'm not sure if I simiplfied to little or to much my LCD is (b-2)(b+2)(b-6) {{{(-1)(b      Log On


   

Question 522695: Please help me solve this :+%28-1%29%2F%28b%5E2-4%29-%28-2%29%2F%28b%5E2-4b-12%29+
Here is what I have I'm not sure if I simiplfied to little or to much my LCD is (b-2)(b+2)(b-6)
%28-1%29%28b-6%29%2F%28b-2%29%28b%2B2%29%28b-6%29-%28-2%29%28b-2%29%2F%28b-2%29%28b%2B2%29%28b-6%29
I'm left with this after I multiply by LCD and do the subtraction -b+6+2b-4= b+2
%28b%2B2%29%2F%28b-2%29%28b%2B2%29%28b-6%29
Any help is very much appreciated.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(-1)/(b^2-4)}}}-%28-1%29%2F%28b%5E2-4%29%7D%7D%7D-(-2)/(b^2-4b-12)
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Factor where you can:
[-1/(b-2)(b+2)] - [-2/(b-6)(b+2)]
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lcd = (b-2)(b+2)(b-6)
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Rewrite each fraction with the lcd as its denominator:
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[-(b-6)]/lcd - (-2(b+2)]/lcd
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Combine the numerators over the lcd:
---
[-b+6-2b-4]/lcd
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Simplify:
[-3b+2]/[(b^2-4)(b-6)]
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Cheers,
Stan H.
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