Question 522644: In a factory, historically it is known that the probability of any randomly selected lot being defective is 0.45. If out of total consignment of 200 lots, 15 lots are randomly selected, then find the probability that,
1. Exactly 7 are defective.
2. At most 6 six are defective
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a factory, historically it is known that the probability of any randomly selected lot being defective is 0.45. If out of total consignment of 200 lots, 15 lots are randomly selected, then find the probability that,
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Binomial Problems with n = 15 and p(defect) = 0.45
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1. P(Exactly 7 are defective) = 15C7*(0.45)^7*(0.55)^8 = 0.2013
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2. P(At most 6 six are defective) = binomcdf(15,0.45,6) = 0.4522
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Cheers,
Stan H.
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