SOLUTION: Please help me with this! I don't know how to do this.
I have to write this equation in vertex form.
The vertex of the parabola is the origin. Point P (1,7) lies on the graph of
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-> SOLUTION: Please help me with this! I don't know how to do this.
I have to write this equation in vertex form.
The vertex of the parabola is the origin. Point P (1,7) lies on the graph of
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Question 522402: Please help me with this! I don't know how to do this.
I have to write this equation in vertex form.
The vertex of the parabola is the origin. Point P (1,7) lies on the graph of the parabola.
Thank you so much. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I have to write this equation in vertex form.
The vertex of the parabola is the origin. Point P (1,7) lies on the graph of the parabola.
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Plot those two points.
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Form of the equation: y = a(x-h)^2+k
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(h,k) is vertex
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h= 0 and k = 0
y = ax^2
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Use point) (1,7) to solve for "a":
7 = a*1^2
a = 7
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Equation:
y = 7x^2
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Cheers,
Stan H.
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