SOLUTION: Find the area of a rectangle whose length is 6 inches less than 5 times the width and whose perimeter is 8 inches more than twice the length.
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Question 522392: Find the area of a rectangle whose length is 6 inches less than 5 times the width and whose perimeter is 8 inches more than twice the length. Answer by solver91311(24713) (Show Source):
The perimeter of a rectangle is twice the length plus twice the width. So if the perimeter is twice the length plus 8, twice the width has to be 8. Width = 4 and you can calculate the length for yourself.
John
My calculator said it, I believe it, that settles it
