SOLUTION: Factor completely (trinomial)
-9xy^2+27y-3x^2y
I tried setting it up with descending variables, but can't get it to work.
-3x^2y-9xy^2+27=
-3y(x^2+3xy-9)=
-3y (x ) (x ) t
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Factor completely (trinomial)
-9xy^2+27y-3x^2y
I tried setting it up with descending variables, but can't get it to work.
-3x^2y-9xy^2+27=
-3y(x^2+3xy-9)=
-3y (x ) (x ) t
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Question 522216: Factor completely (trinomial)
-9xy^2+27y-3x^2y
I tried setting it up with descending variables, but can't get it to work.
-3x^2y-9xy^2+27=
-3y(x^2+3xy-9)=
-3y (x ) (x ) there aren't 2 numbers that multiply to make negative 9 and add to make a positive 3.
Thank you,
Brenda Floyd Answer by Edwin McCravy(20060) (Show Source):
You did nothing wrong. The final answer is -3y(x² + 3xy - 9)
Not all trinomials are factorable (using integers). It is
important that students recognize the ones that are not factorable
and not try to factor them. So leave the answer as:
-3y(x² + 3xy - 9)
Some students, not you of course, would try to factor it and
think the answer would be .
Edwin
