You can put this solution on YOUR website! what is the maximum possible area in square inches of a rectangle with a perimeter of 20 inches?
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Given: P = 2l + 2w = 20
Solve for l in terms of w:
l + w = 10 -> w = 10 - l
The area of the rectangle is:
A = l*w = l(10-l)
The area will be a maximum where dA/dl = 0
dA/dl = 0 = 10 - 2l
This gives l = 5
Therefore, the maximum area = 5*5 = 25 sq. in.
