SOLUTION: given log base 16 of u = 3.7 log base 4 of u^100 how do i go about solving this?

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Question 521866: given log base 16 of u = 3.7
log base 4 of u^100
how do i go about solving this?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
given log base 16 of u = 3.7
log base 4 of u^100
how do i go about solving this
**
log16(u)=3.7
u=16^3.7
..
log4(u^100)=log4[(16^3.7)^100]=log4[16^3700]
Exponential form: base(4) raised to log of number(x)=number(16^3700)
4^x=16^3700=(4^2)^3700=4^7400
x=7400
log4(u^100)=7400
u^100=4^7400
take log of both sides
100logu=7400log4
logu=7400*log4/log100=7400*log4/2=2227.6
u=10^2227.6