SOLUTION: Find three consecutive odd intergers such that the sum of the first, two times the second, and three times the third is 82. this has me stumped

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Find three consecutive odd intergers such that the sum of the first, two times the second, and three times the third is 82. this has me stumped       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 52170: Find three consecutive odd intergers such that the sum of the first, two times the second, and three times the third is 82. this has me stumped
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
THE THREE NUMBERS ARE X,X+2 & X+4 SO X+2(X+2)+3(X+4)=82 THUS X+2X+4+3X+12=82 OR
6X+16=82 0R 6X=82-16 OR 6X=66 OR X=66/6 OR X=11 THUS THE OTHER TWO NUMBERS ARE
11+2=13 & 11+4=15
PROOF 11+2*13+3*15=82 OR 11+26+45=82 OR 82=82