SOLUTION: Hi, I have to solve the following for x e^2ln(2x)=4 I have done (2x)^2=4 4x^2=4 x^2=1 so x would be the squareroot of 1 is this correct?? thanks for your time!

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi, I have to solve the following for x e^2ln(2x)=4 I have done (2x)^2=4 4x^2=4 x^2=1 so x would be the squareroot of 1 is this correct?? thanks for your time!      Log On


   

Question 52133: Hi, I have to solve the following for x
e^2ln(2x)=4
I have done (2x)^2=4
4x^2=4
x^2=1
so x would be the squareroot of 1
is this correct??
thanks for your time!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
correct.
x = plus or minus the square root of one.
so, x+=+%2B1 and x+=+-1