SOLUTION: I need to graph 2y-4x<8 I'm not quite sure how to do this, could you help me? Thanks

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Question 5208: I need to graph 2y-4x<8
I'm not quite sure how to do this, could you help me?
Thanks

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
One way to solve this is to first solve for y by adding +4x to each side:
2y - 4x < 8
2y - 4x + 4x < 4x + 8
2y < 4x+ 8

Next divide both sides by 2:
%282y%29%2F2+%3C+%284x%29%2F2+%2B+8%2F2
y+%3C+2x+%2B+4
You can graph the equation y = 2x +4, by seeing that the y-intercept is 4, and the slope is 2 or 2%2F1+=+%28rise%29%2F+%28run%29. The result of this equation is graphed below.

+graph+%28300%2C300%2C+-10%2C+10%2C+-10%2C+10%2C+4x%2B4%29+

Now, what the inequality y+%3C+2x+%2B+4 calls for is to use a dotted line (since this does NOT include the line), and because the problem calls for y <, you shade below the line. If it had been y> 2x + 4, then you would have shaded ABOVE the line. One more detail, this rule about shading above (for y> ) and below the line (for Y < ) this rule only applies when y has a positive coefficient. Unfortunately, I haven't learned to graph a shaded area in this website yet. Maybe Ichudov will show us how to do this here. Until then, you'll have to do this for yourself: Graph this with a dotted line, and shade below the line.

I hope that is helpful and not confusing.

R^2 at SCC