Question 520513: What 3 consecutive integers add up to 5961?
Answer by tinbar(133)   (Show Source):
You can put this solution on YOUR website! Let the first number be x, then the next two consecutive numbers can be represented by x+1 and x+2. Now we know that x +(x+1)+(x+2) = 5961
Simplifying the left side we get 3x+3=5961
then 3x = 5958
x = 1986.
Therefore the 3 consecutive numbers are 1986, 1987, and 1988.
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