SOLUTION: OK. I have 6(t+w)to the second +11(t+w)-10 The book gives me this answer (3t+3w-2)(2t+2w+5)I can see where the numbers are from the original equation but I don't see how to get

Algebra ->  Sequences-and-series -> SOLUTION: OK. I have 6(t+w)to the second +11(t+w)-10 The book gives me this answer (3t+3w-2)(2t+2w+5)I can see where the numbers are from the original equation but I don't see how to get       Log On


   

Question 520369: OK. I have 6(t+w)to the second +11(t+w)-10
The book gives me this answer (3t+3w-2)(2t+2w+5)I can see where the numbers are from the original equation but I don't see how to get there. How would you determine that you would not use a (nx+b)(nx-c) format and you would have to use 3 numbers in each set?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I think that you are saying you have:



And you want to factor it.

What I would do, and this is just me, would make a simple substitution so that the quadratic doesn't look quite so ugly. Like this:

Let , then substitute:



Which factors rather tidily to:



Then substitute back:



Then distribute:



John

My calculator said it, I believe it, that settles it
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