You can
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x + 3
-------- = 3
2
Put the 3 over 1 so everything will be fractions:
x + 3 3
-------- = ---
2 1
The LCD of 2 and 1 is 2. So multiply both sides by
2 over 1:
2 x + 3 2 3
--- · -------- = --- · ---
1 2 1 1
We cancel the 2's on the left and multiply the
numerators 2·3, getting 6, and denominators 1·1,
getting 1 on the right:
1
2 x + 3 6
--- · -------- = ---
1 2 1
1
So we can ignore the 1's on the bottome and just have
x + 3 = 6
which you should have no trouble solving.
Edwin