SOLUTION: Hi, I have to suppose the vertex of the parabola y=3x^2-6x+k is (1,2) I have to find k. I have substituted x=1 and y=2 into the equation and got 2=3(1)^2 - 6(1) +k 2= 3-6+k 2-3

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Hi, I have to suppose the vertex of the parabola y=3x^2-6x+k is (1,2) I have to find k. I have substituted x=1 and y=2 into the equation and got 2=3(1)^2 - 6(1) +k 2= 3-6+k 2-3      Log On


   



Question 52025: Hi, I have to suppose the vertex of the parabola y=3x^2-6x+k is (1,2) I have to find k.
I have substituted x=1 and y=2 into the equation and got
2=3(1)^2 - 6(1) +k
2= 3-6+k
2-3+6=k
k=5
Is this right??? thanks.

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
It looks right to me!!

R^2 at SCC