Question 520239: Please help!
If an object is thrown upward with an initial velocity of 16 ft/sec, its height, h, in feet, after t seconds is given by h=16t-16t^2 Find the number of seconds before the object hits the ground. (Round your answer to the nearest tenth, if necessary.)
Thank you!!
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! If an object is thrown upward with an initial velocity of 16 ft/sec, its height, h, in feet, after t seconds is given by h=16t-16t^2 Find the number of seconds before the object hits the ground. (Round your answer to the nearest tenth, if necessary.)
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It hits the ground when h = 0
h=16t-16t^2 = 0
t = 0 (when it's starts)
t = 1 second at impact
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