SOLUTION: Cecily can ride her bike 4mph faster than her husband, Mike. If Cecily can ride 48 mi in the same time that mike can ride 24 mi, what are their speeds?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Cecily can ride her bike 4mph faster than her husband, Mike. If Cecily can ride 48 mi in the same time that mike can ride 24 mi, what are their speeds?      Log On


   



Question 520128: Cecily can ride her bike 4mph faster than her husband, Mike. If Cecily can ride 48 mi in the same time that mike can ride 24 mi, what are their speeds?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Cecily can ride her bike 4mph faster than her husband, Mike. If Cecily can ride 48 mi in the same time that mike can ride 24 mi, what are their speeds?
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let x=Mike's speed in mph
x+4=Cecily's speed in mph
travel time=distance/speed (same for both)
48/(x+4)=24/x
48x=24x+96
24x=96
x=4
ans:
Mike's speed=4 mph
Cecily's speed=8 mph