SOLUTION: Let csc &#952; = 19/6 , 0 < &#952; < pi/2 sin&#952;= 6/19 Find: cos&#952;, tan&#952;, sec&#952;, and cot&#952;. How do you solve this?

Algebra ->  Trigonometry-basics -> SOLUTION: Let csc &#952; = 19/6 , 0 < &#952; < pi/2 sin&#952;= 6/19 Find: cos&#952;, tan&#952;, sec&#952;, and cot&#952;. How do you solve this?      Log On


   

Question 519991: Let csc θ = 19/6 , 0 < θ < pi/2
sinθ= 6/19 Find: cosθ, tanθ, secθ, and cotθ.
How do you solve this?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Let csc θ = 19/6 , 0 < θ < pi/2
sinθ= 6/19 Find: cosθ, tanθ, secθ, and cotθ.
How do you solve this?
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You are working in quadrant I where all the trig functions are>0
Given:
opposite side=6
hypotenuse=19
adjacent side=√(19^2-6^2)=√325
Trig functions:
sinθ=6/19 (given)
cosθ=√325/19
tanθ=6/√325
cscθ=19/6
secθ=19/√325
cotθ=√325/6