SOLUTION: Find the x intercepts. y=x^2-9x+20

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Question 51988: Find the x intercepts.
y=x^2-9x+20
Answer by THANApHD(104) About Me  (Show Source):
You can put this solution on YOUR website!
intercepts mean th x's values when the y = 0.

0=x^2-9x+20
0=x^2-5x-4x+20
0=x(x-5)-4(x-5)
0=(x-4)(x-5)
so either one this must be zero
x-4 = 0 or x-5=0
x= 4 or x=5