SOLUTION: Find the vertex, x and y intercepts of the parabola given by the equation Y=3x2 -2x+1

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Question 519484: Find the vertex, x and y intercepts of the parabola given by the equation
Y=3x2 -2x+1
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
y = 3x^2 -2x +1
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+graph%28500%2C500%2C-5%2C5%2C-5%2C5%2C3%2Ax%5E2-2x%2B1%29+
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Axis is symmetry = -b/2a = -(-2)/2(3) = 2/6 = 1/3
x = 1/3
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Vertex is point on the axis of symmetry defined by x=1/3
y = 3(1/3)^2 - 2(1/3) + 1
y = 3/9 - 2/3 +1
y = 3/9 - 6/9 + 9/9
y = 6/9 = 2/3
(1/3, 2/3)
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y-intercept occurs when x=0, which is 1.
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The equation does not factor, so the quadratic equation may be tried.
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+x+=+%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29+
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For these solutions to exist, the discriminant b^2-4ac should not be a negative number.
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In this case the discriminant is -8. That means that there are no solutions among real numbers.