SOLUTION: Write an equation in slope intercept form satisfying the given conditions (Please?): The line passes through (4,-7) and is perpendicular to the line whose equation is x - 2y = 3

Algebra ->  Linear-equations -> SOLUTION: Write an equation in slope intercept form satisfying the given conditions (Please?): The line passes through (4,-7) and is perpendicular to the line whose equation is x - 2y = 3      Log On


   

Question 519457: Write an equation in slope intercept form satisfying the given conditions (Please?):
The line passes through (4,-7) and is perpendicular to the line whose equation is x - 2y = 3.
Found 2 solutions by stanbon, nerdybill:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation in slope intercept form satisfying the given conditions (Please?):
The line passes through (4,-7) and is perpendicular to the line whose equation is x - 2y = 3.
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Determine the slope of the given line.
2y = x-3
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y = (1/2)x - (3/2)
slope of the given line is 1/2
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Therefore slope of any perpendicular line must be -2
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Form of needed equation: y = mx + b
y = -7 when x = 4 and the slope is -2
Solve for "b":
-7 = -2*4 + b
b = 1
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Equation:
y = -2x +1
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Cheers,
Stan H.
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Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
The line passes through (4,-7) and is perpendicular to the line whose equation is x - 2y = 3.
.
First, determine slope of:
x - 2y = 3
-2y = -x + 3
2y = x - 3
y = (1/2)x - 3/2
slope is 1/2
.
Slope of new line is negative reciprocal:
(1/2)m = -1
m = -2
slope if new line -2
.
plug given point (4,-7) and slope (-2) into "point-slope" form:
y - y1 = m(x - x1)
y - (-7) = -2(x - 4)
y + 7 = -2x + 8
y = -2x + 1 (this is what they're looking for in "slope-intercept" form)