SOLUTION: How to & steps to solve:
Justin drove to his parents 175 miles away. On his way there his speed averaged 24 times faster then on his way back. He drove a total of 5 hours. What wa
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Justin drove to his parents 175 miles away. On his way there his speed averaged 24 times faster then on his way back. He drove a total of 5 hours. What wa
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Question 519427: How to & steps to solve:
Justin drove to his parents 175 miles away. On his way there his speed averaged 24 times faster then on his way back. He drove a total of 5 hours. What was his speed on the way there and on the way back?
I've solved it to:
175s+175(5+24)=5s(s+24)
But I'm stuck there. I don't know what to do next. Found 2 solutions by ankor@dixie-net.com, josmiceli:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Justin drove to his parents 175 miles away.
On his way there his speed averaged 24 times faster than on his way back.
He drove a total of 5 hours.
What was his speed on the way there and on the way back?
:
Let s = his speed back
then
24s = his speed there
:
Write time equation: time = dist/speed
:
There time + return time = 5 hrs + = 5
Multiply by 24s, results
175 + 24(175) = 24s(5)
175 + 4200 = 120s
4375 = 120s
s =
s = 36.46 mph on the way back
then
24(36.46) = 875 mph on the way there, must have used an F-16 Jet
You can put this solution on YOUR website! Let = his speed on the way back
Let = his time on the way back
given: = his speed going = one way distance = his time going
----------------------
Going to parents:
(1)
Coming back:
(2)
Substitute (2) into (1)
(1)
(1)
(1)
(1) mi/hr mi/hr
-----------------------
check:
(2)
(2)
(1)
(1)
(1)
(1)
and
(2)
(2)
I think there is something wrong with the data,
maybe a miscopy. The speed going can't be
875 mi/hr
I rechecked my math- I think it's OK
Is the right?
