SOLUTION: A box 12 feet by 15 feet by 20 feet contains 988,676, 1.5 inch diameter balls. What percent of empty space remains in this box?

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Question 519359: A box 12 feet by 15 feet by 20 feet contains 988,676, 1.5 inch diameter balls. What percent of empty space remains in this box?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A box 12 feet by 15 feet by 20 feet contains 988,676, 1.5 inch diameter balls. What percent of empty space remains in this box.
:
Find the volume of the box
12 * 15 * 20 = 3600 cu/ft
Convert to cu inches
3600 * 12^3 = 6,220,800 cu/in
:
Find the vol of the ball, 1.5/2 = .75" the radius of the ball
V = 4%2F3*pi%2A.75%5E3
V = 1.767146 cu/in in one ball
then
988676 * 1.787146 = 1,747,134.7 cu/inches for this many balls
:
Find the unused space:
6220800 - 1747134.7 = 4,473,665.3 cu/inches of empty space