SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph and train B is traveling at 100mph. Train A passes a station at 2:20 PM. If tr

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Question 519332: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph and train B is traveling at 100mph. Train A passes a station at 2:20 PM. If train B passes the same station at 2:32 PM, at what time will train B catch up to train A?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 80 mph and train B is traveling at 100mph.
Train A passes a station at 2:20 PM.
If train B passes the same station at 2:32 PM, at what time will train B catch up to train A?
:
From the given information, we know that Train B is 12 min behind A at at 2:20 pm
therefore Train B is:
12%2F60 * 100 = 20 miles behind Train A at that time.
:
Let t = time required for Train B to catch Train A
:
Write a distance equation; dist = speed * time
:
Train B dist = Train A dist + 20 mi
100t = 80t + 20
10t - 80t = 20
20t = 20
t = 1 hr for B to catch A
:
Find the time from 2:20 pm:
2;20 + 1:00 = 3:20 pm, Train B catches Train A