SOLUTION: For what values in the interval 0<x<180 is 2-4 sin 2x < 0?

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Question 519114: For what values in the interval 0 2-4 sin 2x < 0?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
For what values in the interval 0<180 is
2-4 sin 2x < 0
**
2-4 sin 2x < 0
-4sin 2x<-2
divide by -4 and reverse inequality sign
sin 2x>-2/-4=1/2
2x>30º
x>30/2=15º
The interval 0-180 are quadrants I and II where sin>0
Solutions:180º>x>15º and 180º>x>165º