SOLUTION: Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.
cos^2 x- sin^2 x = sqr3/2
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-> SOLUTION: Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.
cos^2 x- sin^2 x = sqr3/2
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Question 519106: Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.
cos^2 x- sin^2 x = sqr3/2 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.
cos^2 x- sin^2 x = sqr3/2
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cos^2x-sin^2x=√3/2
1-sin^2x-sin^2x=√3/2
1-sin^2x-(1-cos^2x)=√3/2
1-sin^2x-1+cos^2x=√3/2
cos^2x-sin^2x=√3/2
cos(2x)=√3/2
2x=π/6
x=π/12
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