SOLUTION: 1.) Andre rode in a bike trek from his home due north for 10 miles and then due east for 3 miles. How far, to the nearest tenth, is he from home after his first day?
2.) He con
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-> SOLUTION: 1.) Andre rode in a bike trek from his home due north for 10 miles and then due east for 3 miles. How far, to the nearest tenth, is he from home after his first day?
2.) He con
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Question 519105: 1.) Andre rode in a bike trek from his home due north for 10 miles and then due east for 3 miles. How far, to the nearest tenth, is he from home after his first day?
2.) He continues north for another 12 miles and then turned west and rode for 15 miles. At the end of the second day, how far was he from the first night's stop?
3.) The third day he headed north and rode for 17 miles and west for 10 miles. How far is he from his seconds nights stop?
How many miles south must he ride to be able to turn east and ride straight home?
Im so sorry i know this is more then one question but they all have to do with number one so i didnt know how else to do this! please help me! Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Each one of these problems can be solved by finding the hypotenuse of a right triangle:
:
1.) Andre rode in a bike trek from his home due north for 10 miles and then due east for 3 miles.
How far, to the nearest tenth, is he from home after his first day?
h = 10.4 mi
:
2.) He continues north for another 12 miles and then turned west and rode for 15 miles.
At the end of the second day, how far was he from the first night's stop?
h = 19.2 mi
:
3.) The third day he headed north and rode for 17 miles and west for 10 miles.
How far is he from his seconds nights stop?
h = 19.7 mi
:
How many miles south must he ride to be able to turn east and ride straight home?
Add up the total miles traveled north, to find the required miles south.
10 + 12 + 17 = 39 miles south then turn east
