This system
becomes
You didn't say to solve it, but I will anyway, because no doubt
you'll be given some later to solve, and you can use this as a
model to go by:
To solve it find the inverse of the coefficient matrix, which is
Then left-multiply both sides of the matrix equation by this inverse:
Multiply the first two matrices on the left, and multiply the
matrices on the right:
Multiplying the matrices on the left (the one on the left is the identity
matrix)
So the solution is x=2, y=1, z=-1.
Edwin