SOLUTION: A university bookstore recently sold a wirebound graph-paper notebook for $2.60, and a college-ruled notebook for $2.45. At the start of spring semester, a combination of 75 of th

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A university bookstore recently sold a wirebound graph-paper notebook for $2.60, and a college-ruled notebook for $2.45. At the start of spring semester, a combination of 75 of th      Log On


   

Question 518876: A university bookstore recently sold a wirebound graph-paper notebook for $2.60, and a college-ruled notebook for $2.45. At the start of spring semester, a combination of 75 of these notebooks were sold for a total of $191.25. How many of each type were sold?
Answer by Maths68(1474) About Me  (Show Source):
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Price per wirebound graph-paper notebook = $2.60
Price per college-ruled notebook = 2.45$
Number of wirebound graph-paper notebook sold = x
Number of college-ruled notebook sold = 75-x
Total Amount = 191.25
2.60*(Number of WG notebook) + 2.45*(Number of CR notebook) = Total
2.60*(x) + 2.45*(75-x) = 191.25
2.60x+183.75-2.45x=191.25
2.60x-2.45x=191.25-183.75
0.15x=7.5
0.15x/0.15=7.5/0.15
x=50
Number of wirebound graph-paper notebook sold = x = 50
Number of college-ruled notebook sold = 75-x = 75-50 = 25
Check
=====
50*2.60 + 25*2.45 = 191.25
130+61.25=191.25
191.25=191.25