SOLUTION: My word problem is:
A car and a motor cycle leave a rest area at the same time, with the car traveling 8 mph faster than the motorcycle. The car then travels 105 mi in the time i
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A car and a motor cycle leave a rest area at the same time, with the car traveling 8 mph faster than the motorcycle. The car then travels 105 mi in the time i
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Question 518179: My word problem is:
A car and a motor cycle leave a rest area at the same time, with the car traveling 8 mph faster than the motorcycle. The car then travels 105 mi in the time it takes the motorcycle to travel 93 mi. Find the speed of each vehicle. Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! d = r*t is the basic distance equation
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Car:
d = 105 miles
r = speed of motorcycle +8 = s+8
t = same as motorcycle = d/r = 105/(s+8)
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Motorcycle:
d = 93 miles
r = speed of motorcycle = s
t = same as the car = d/r = 93/s
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t = t
so
105/(s+8) = 93/s
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cross multiply
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105*s = (s+8)*93
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105s = 93s + 744
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12s = 744
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s = 62 mph = motorcyle's speed
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s + 8 = 70 mph = car's speed
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Check the answer:
How long does it take the car to travel 105 miles?
105/70 = 3/2
How long does it take the motorcycle to travel 93 miles?
93/62 = 3/2
Correct.
.
Done.
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