SOLUTION: a number is divided by 7. Then 19 is added to the quotient. Next 8 is subtracted from the sum. The resulting number is the product of 9 times itself. What is the original number?

Algebra ->  Equations -> SOLUTION: a number is divided by 7. Then 19 is added to the quotient. Next 8 is subtracted from the sum. The resulting number is the product of 9 times itself. What is the original number?      Log On


   



Question 518024: a number is divided by 7. Then 19 is added to the quotient. Next 8 is subtracted from the sum. The resulting number is the product of 9 times itself. What is the original number?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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a number is divided by 7. Then 19 is added to the quotient. Next 8 is subtracted from the sum. The resulting number is the product of 9 times itself. What is the original number?
:
n%2F7 + 19 - 8 = 9^2
:
n%2F7 + 11 = 81
:
n%2F7 = 70
:
multiply both sides by 7
n = 7(70)
:
n = 490
:
:
Check in the original statement
490%2F7 + 19 - 8 = 9^2
70 + 19 - 8 = 81